为啥运行不了，还有char后加*啥意思 求解谢谢
#include<stdio.h>int nain()
{
char* sn[5];
int age[5]={11,13,12,13,14};
int i;
sn[0]="zzk";
sn[1]="yjx";
sn[2]="gu";
sn[3]="zl";
sn[4]="zf";
for(i=0;i<5;i++)
{
printf("%s\n",sn[i]);
printf("%d\n",age[i]);
}
return 0;
}
