#include<stdio.h>
int nain()
{
    char* sn[5];
    int age[5]={11,13,12,13,14};
    int i;
    sn[0]="zzk";
    sn[1]="yjx";
    sn[2]="gu";
    sn[3]="zl";
    sn[4]="zf";
    for(i=0;i<5;i++)
    {
        printf("%s\n",sn[i]);
        printf("%d\n",age[i]);
    }
    return 0;
}

int nain()
int main()

char* 是char指针类型

谢谢