把大写字母转换成小写字母.　　转换规则自定:如 A转换成BcBc  ;B转换成dc(这里如果输入AB,则输出dccdccdc) 之类的 (不过可能输入全部２６个字母，其他字母规则自己设定）      总之输入的大写最后要全部转换成小写(好象这里面有递归,又不知道怎么实现)求高手指点一下!谢谢!

[此贴子已经被作者于2006-10-12 23:28:19编辑过]

不会吧,高手快来help me啊 !焦急等待中啊!

A->a,B->b,…………
这样可以不，看下ASCII表

这样不行啊　　一定要复杂些的啊　　如 A转换成BcBc ;B转换成dc(这里如果输入AB,则输出dccdccdc)

看不懂这种转换

#include <iostream>
using namespace std;
char * b[] = {"BcBc","dc","Ac","df","io","Jk","MnoP","jh","dio","dic","MA","id","nm",
"kd","Hkd","ki","fd","cd","kdo","nm","hj","iod","cid","am","dm","xy"};
void f(char a1[],int n,char *b1[])
{
const int size = strlen(b1[n]);
char * c1 = b1[n];
for(int i = 0;i < size;i++)
{
if(c1[i] >= 'a' && c1[i] <= 'z')
cout<<c1[i];
else
{
for(int j = 0;j < 26 && a1[j] != c1[i];++j);
f(a1,j,b1);
}
}
}
int main()
{
char a[26] = {'A','B','C','D','E','F','G','H','J','K','L','M','N','O','P','Q','R','S','T',
'U','V','W','X','Y','Z'};
char c[2];
int j;
cin>>c;//输入AB
for(int i = 0;i < 2;i++)
{
if(c[i] >= 'a' && c[i] <= 'z')
cout<<c[i];
else
{
for(j = 0;j < 26 && a[j] != c[i] ;++j);
f(a,j,b);
}

}
cout<<endl;
system("pause");
return 0;
}

[此贴子已经被作者于2006-10-14 11:20:28编辑过]

谢谢拉　楼上的．不过不知道Ｃ＋＋里面的map之类的可不可以实现？

map&lt;char,string&gt;应该可以吧

怎么转换?什么规律?
看不懂

无聊死了