#include<stdio.h>                    //程序的目的是 每次从5个颜色中取出3种 有多少种取法 然后输出排列情况
int main()
{    enum Color{red,yellow,blue,white,black};
    enum Cclor i,j,k,pri;
    int n,loop;
    n=0;
    for(i=red;i<=black;i++)
    {    for(j=red;j<=black;j++)
        {
            if(i!=j)
            {    for(k=red;k<=black;k++)
                {   
                    if((k!=i)&&(k!=j))
                    {    n=n+1;
                        printf("%-4d",n);
                        for(loop=1;loop<=3;loop++)
                        {    switch(loop)
                            {    case 1:    pri=i;break;
                                case 2: pri=j;break;
                                case 3: pri=k;break;
                                default: break;
                            }
                            switch(pri)
                            {    case red: printf("%-10s","red"); break;
                                case yellow: printf("%-10s","yellow"); break;
                                case blue: printf("%-10s","blue"); break;
                                case white: printf("%-10s","white"); break;
                                case black: printf("%-10s",black); break;
                                default: break;
                            }
                        }
                        printf("\n");
                    }
                }
            }
        }
    }
    printf("\ntotal:%5d\n",n);
    return 0;
}

倒数第十三行  case black: printf("%-10s",black); break; black需要双引号吧

我用的VC6.0没enum库
稍微改了下
如下：

#include<stdio.h>                    //程序的目的是 每次从5个颜色中取出3种 有多少种取法 然后输出排列情况
int main()
{    int a[5] = {1, 2, 3, 4,5};
    int Cclor,i,j,k,pri;
    int n,loop;
    n=0;
    for(i=1;i<=5;i++)
    {    for(j=1;j<=5;j++)
        {
            if(i!=j)
            {    for(k=1;k<=5;k++)
                {   
                    if((k!=i)&&(k!=j))
                    {    n=n+1;
                        printf("%-4d",n);
                        for(loop=1;loop<=3;loop++)
                        {    switch(loop)
                            {    case 1:    pri=i;break;
                                case 2: pri=j;break;
                                case 3: pri=k;break;
                                default: break;
                            }
                            switch(pri)
                            {    case 1: printf("%-10s","red"); break;
                                case 2: printf("%-10s","yellow"); break;
                                case 3: printf("%-10s","blue"); break;
                                case 4: printf("%-10s","white"); break;
                                case 5: printf("%-10s","black"); break;
                                default: break;
                            }
                        }
                        printf("\n");
                    }
                }
            }
        }
    }
    printf("\ntotal:%5d\n",n);
    return 0;
}

楼主看下 行不

运行了一下好像没问题 给你个

#include <stdio.h>

int main( void )
{
    char    *color[5]={ "red", "yellow", "blue", "whie", "black"};
    int    i, j, k, n=0;
    for( i=0; i<5; i++ )
        for( j=0; j<5; j++ )
            if( i!=j )
                for( k=0; k<5; k++ )
                    if( k!=i && k!=j )
                    {
                        n++;
                        printf("%4d%10s%10s%10s\n", n, color[i], color[j], color[k]);
                    }
    return 0;
}

[ 本帖最后由 yxiangyxiang 于 2012-2-12 17:15 编辑 ]

楼上的 代码好看

这个貌似在大学课本上看过

打印C(5,3)

#include <stdio.h>
int data[100] = {5,4,3,2,1};
bool foot[100] = {0};
int cool = 0;
void com(int n,int k,int mem[],int depth,int begin,int pos)
{
    int i,j;
    if(k == depth)
    {
        for(i = 0;i<k;i++)
            printf("%d ",mem[i]);
        cool++;
        printf("\n");
        return ;
    }
    for(i = pos;i<n;i++)
    {
        if(!foot[i])
        {
            foot[i] = true;
            mem[begin] = data[i];
            com(n,k,mem,depth+1,begin+1,i+1);
            foot[i] = false;
        }
    }
}
int main()
{
    int mem[100] = {0};
    com(5,3,mem,0,0,0);
    return 0;
}

 
 

代码太多嵌套了，不想看

谢谢各位

楼主的代码看起来很有型；