大家看看我这个怎么回事，写个简单的选择题，但是如果不选c p t q的话程序要一直提示重新输入，但是我写不出来，试过加循环，但是不知道怎么加好，哪位高手能告诉我怎么加个循环
# include <iostream>
int main()
{using namespace std;
 cout<<"Please enter one of the following choices:";
 cout<<"c)carnivore\t"<<"p)paianist"
     <<"t)tree\t"<<"q)game";
 char ch;
 cout<<"please enter  c,p,t or q:";

 cin>>ch;


 switch(ch)
 { case 'c' : cout<<"A maple is carnivore\t";
    break;
   case 'p' : cout<<"A maple is paianist\v";
    break;
   case 't' : cout<<"A maple is tree\t";
    break;
   case 'q' : cout<<"A maple is game\v";
    break;
   default : cout<<"please enter a c,p,t or q:";


}
  system("pause");
  return 0;
}

以下是我的思路。欢迎不同意见的朋友发帖交流。
# include <iostream>
int main()
{
    using namespace std;
    
    int XunHuan=1;
    char ch;

    while(XunHuan)
    {
        
        cout<<"Please enter one of the following choices:";
        cout<<"c)carnivore\t"<<"p)paianist"
            <<"t)tree\t"<<"q)game";
    
        cout<<"please enter  c,p,t or q:";
        
        cin>>ch;
        
        if(ch=='c'||ch=='p'||ch=='t'||ch=='q')
        {
            XunHuan=0;
        }
        else
        {
            XunHuan=1;
            cout<<"You Have Made A Wrong Choice."<<endl;
        }
        
    }
    
    switch(ch)
    { case 'c' : cout<<"A maple is carnivore\t";
    break;
    case 'p' : cout<<"A maple is paianist\v";
        break;
    case 't' : cout<<"A maple is tree\t";
        break;
    case 'q' : cout<<"A maple is game\v";
        break;
    default : cout<<"please enter a c,p,t or q:";
        
        
    }
    
    return 0;
}

[[it] 本帖最后由 VanHorn 于 2008-3-16 15:30 编辑 [/it]]

这个思路不错，可是怎么用循环实现呢？我想用循环实现的

一楼那位写的就是循环啊，while也是循环啊。

循环分为while和for循环

char str;
cin>> str;
  cin>>str;
while((srt=='c')?0:(srt=='p'))?0:(srt=='t')?0:(srt=='q'))
{
  
switch(str)
{ case 'c' : cout<<"A maple is carnivore\t";
    break;
   case 'p' : cout<<"A maple is paianist\v";
    break;
   case 't' : cout<<"A maple is tree\t";
    break;
   case 'q' : cout<<"A maple is game\v";
    break;
   default : cout<<"please enter a c,p,t or q:";
    cin>>str;


}

}
你试试，应该成立。

((srt=='c')?0:(srt=='p'))?0:(srt=='t')?0:(srt=='q')？0:1)
写错了。。。。
拉一步

# include <iostream>
int main()
{using namespace std;
cout<<"Please enter one of the following choices:";
cout<<"c)carnivore\t"<<"p)paianist"
     <<"t)tree\t"<<"q)game";
char ch;
cout<<"please enter  c,p,t or q:";

    do
    {
         cin>>ch;
        switch(ch)
        { case 'c' : cout<<"A maple is carnivore\t";
            break;
           case 'p' : cout<<"A maple is paianist\v";
            break;
           case 't' : cout<<"A maple is tree\t";
            break;
           case 'q' : cout<<"A maple is game\v";
            break;
           default : cout<<"please enter a c,p,t or q:";
            
            
        }
    }
while(((ch=='c')?0:(ch=='p')?0:(ch=='t')?0:(ch=='q')?0:1));


  return 0;
}

比较喜欢8楼的程序，简洁些，谢谢了

while(((ch=='c')?0:(ch=='p')?0:(ch=='t')?0:(ch=='q')?0:1)); //不知道这步还有别的简洁方式吗？