Problem Description
Given the gray value of each transformation point of the image in n row m column. After the conversion is performed successively,  please print the final image.
The possible operations and corresponding characters are as follows:
A: Rotate clockwise by 90 degrees;
B: Rotate counterclockwise by 90 degrees ;
C: Flip left and right;
D: Turn upside down.

Input
Multi testcases(<=10).
For each testcase:
    two integers n, m (1 <= n,m <= 100) in the first line
    m integers (0 <= a[i][j] <= 255) in next n lines
    a string s (|s| <= 100) in a line, means the operations.
Output
For each testcase:
    m integers in n lines meas the final image
Sample Input
2 3
10 0 10
100 100 10
AC

Sample Output
10 100
0 100
10 10

感觉无从下手 这个转换

哥 你能解释下代码的意义吗 我看不太懂 而且我指针不是很熟练

请问为啥八种啊? 而且算出来是什么意思 我以为旋转交换是建一个二维数组然后变换数组的位置

我好像知道啥意思了,但您这代码我还是看不懂

  unsigned mode = 0;
        for( const char* p=s; *p; ++p )
        {
            switch( *p )
            {
            case 'A': mode=mode/4*4 + (mode+3)%4; break;
            case 'B': mode=mode/4*4 + (mode+1)%4; break;
            case 'C': mode=(mode+4)%8; break;
            case 'D': mode=mode%4/2*4-2; break;
            }
        }
能讲下这是啥意思吗? 麻烦大佬了

原理啥的悟了  但不知道 for( size_t i=0; i!=r*c; ++i )
            printf( "%hhu%c", a[(first+i*step1+i/line*step2)%(r*c+1)], " \n"[(i+1)%line==0] );
    }
}咋就这么神奇呢

对 版主说的对  啥也不说了 nb