求指教～ 两个没有很大差别的程序 一个可以运行，另一个就中断
可以运行的程序在这里～
程序代码：#include <stdio.h>
#include <ctype.h>
int main()
{
char num[6];
int i,a=0,b=0;
printf("Please input your ID number:\n(including two letters & 4 digits)\n");
for (i=0; i<6; i++)
scanf("%c", &num[i]);
for (i=0; i<2; i++)
{
if(isalpha(num[i]))
a++;
}
for (i=2; i<6; i++)
{
if(isdigit(num[i]))
b++;
}
if (a!=2 || b!=4 )
printf("Wrong!");
else
printf("Please choose an option:\n(1) Start a test\n(2) Check scores\n(3) Exit\n");
return 0;
}
这个程序就不能运行。。。（这只是一部分啦，剩下的还在编，这一部分无法运行。。）
程序代码：#include <stdio.h>
#include <time.h>
#include <stdlib.h>
#include <ctype.h>
int main()
{
int i, a=0, b=0, option;
char no[6];
printf( "This program will help elementary school pupils practice math.\n" );
printf( "Please input your ID number:\n(including two letters and four digits)\n" );
/*Check the ID number*/
for (i=0; i<6; i++)
scanf("%c", no[i]);
for (i=0; i<2; i++)
{
if (isalpha (no[i]))
a++;
}
for (i=2; i<6; i++)
{
if (isdigit (no[i]))
b++;
}
if (a !=2 || b !=4)
printf("PLease check your ID number and run again.\n");
/*start the program*/
else
{
printf("PLease input a number less than 4 to choose an option:\n(1)Start a test\n(2)Check scores\n(3)Exit");
scanf("%d",&option);
do
{
printf("Oh, please choose it again");
}
while (option<4);
switch(option)
{
case 1: printf("yeah");
break;
case 2: printf("wrong");
break;
case 3: return 0;
break;
}
}
return 0;
}
