#include <stdio.h>
int main (void)
{
    int day,year,month,sum,leap;
    printf("please input year,month,day\n");
    scanf("%d,%d,%d",&year,&month,&day);
    switch(month)
    {
    case 1:sum=0;
        break;
    case 2:sum=31;
        break;
    case 3:sum=59;
        break;
    case 4:sum=90;
        break;
    case 5:sum=120;
        break;
    case 6:sum=151;
        break;
    case 7:sum=181;
        break;
    case 8:sum=212;
        break;
    case 9:sum=243;
        break;
    case 10:sum=273;
        break;
    case 11:sum=304;
        break;
    case 12:sum=334;
        break;
    default:
        printf("data error");
        break;
        sum=sum+day;
        if(year%400==0||(year%4==0&&year%100!=0))
            leap=1;
        else
            leap=0;
        if(leap=1&&month>2)
            sum+=1;        
    }
    printf("It is the %dth day of %d year.\n",sum,year);
    return 0;
}

     break;
     default:
         printf("data error");
         break;
               
     }
       sum=sum+day;
         if(year%400==0||(year%4==0&&year%100!=0))
             leap=1;
         else
             leap=0;

     if(leap=1&&month>2)
             sum+=1;        
     printf("It is the %dth day of %d year.\n",sum,year);
     return 0;
 }

这样子写么？

[此贴子已经被作者于2016-3-24 16:28编辑过]

哦

新手，求大神指点一二

有没有更好的方法

我试了试，这两个都行

哦   ok，ok，

哇，真棒，还可以这样

好多写法呀

int dayofmonth[]={0,0,31,28,31,30,31,30,31,31,30,31,30};
这样写好像也行