病急乱投医，仿写了一段VBA代码，怎么得到返回的数据呢？
Sub zyl()
    Set http = CreateObject("MSXML2.XMLHTTP")
    URLNAME = "https://biz.
    lcRq = "2021.12.17"
    lcCode = "300415"
    response = http.Open("POST", URLNAME, False)
    response = http.SETREQUESTHEADER("Content-Type", "application/x-www-form-urlencoded")
    response = http.SEND("queryDate=" + lcRq + "&secCde=" + lcCode)
    Rem 可以运行到这里，下面出现错误
    Print (response.Status())
    Print (respons.RESPONSEBODY)
   
End Sub

我知道为什么了，不应该使用response调用结果，而应该使用http.responseText。thinks anyway.