标题:请教如何将C程序转换C#程序
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头大脑袋疼
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请教如何将C程序转换C#程序
程序代码:
#include <stdio.h>
#include <math.h>
#include <stdlib.h>
#include <time.h>

 
#define SUM 20            //总共的染色体数量
#define MAXloop 1200       //最大循环次数
#define error 0.01        //若两次最优值之差小于此数则认为结果没有改变
#define crossp 0.7        //交叉概率
#define mp 0.04           //变异概率

 
struct gen                //定义染色体结构
{
    int info;        
    float suitability;
};
struct gen gen_group[SUM];//定义一个含有20个染色体的组
struct gen gen_new[SUM];  

 
struct gen gen_result;    //记录最优的染色体
int result_unchange_time; //记录在error前提下最优值为改变的循环次数
 
struct log                //形成链表,记录每次循环所产生的最优的适应度
{
    float suitability;
    struct log *next;
}llog,*head,*end;
int log_num;              //链表长度
 
void initiate();          
void evaluation(int flag);
void cross();
void selection();
int  record();
void mutation();
void showresult(int);

 
int   randsign(float p);
int   randbit(int i,int j);
int   randnum();
int   convertionD2B(float x);
float convertionB2D(int x);
int   createmask(int a);

 
void main()
{
    int i,flag;
    flag=0;
    initiate();
    evaluation( 0 );
    for( i = 0 ; i < MAXloop ; i++ )
    {
        cross();
        evaluation( 1 );
        selection();
        if( record() == 1 )
        {
            flag = 1;
            break;
        }
        mutation();
    }
    showresult( flag );
}

 
void initiate()
{
    int i , stime;  
    long ltime;
    ltime=time(NULL);
    stime=(unsigned)ltime/2;
    srand(stime);
    for( i = 0 ; i < SUM ; i++ )
    {
        gen_group[i].info = randnum();       
    }
    gen_result.suitability=1000;
    result_unchange_time=0;
    head=end=(struct log *)malloc(sizeof(llog));
    if(head==NULL)
    {
        printf("\n内存不够!\n");
        exit(0);
    }
    end->next = NULL;
    log_num = 1;
}

 
void evaluation(int flag)
{
    int i,j;
    struct gen *genp;
    int gentinfo;
    float gentsuitability;
    float x;
    if( flag == 0 )
        genp = gen_group;
    else genp = gen_new;
    for(i = 0 ; i < SUM ; i++)//计算各染色体对应的表达式值
    {
        x = convertionB2D( genp[i].info );
        genp[i].suitability = x*(x*(x*(x*(x*(x-10)-26)+344)+193)-1846)-1680;
    }
    for(i = 0 ; i < SUM - 1 ; i++)//按表达式的值进行排序,
    {
        for(j = i + 1 ; j < SUM ; j++)
        {
            if( genp[i].suitability > genp[j].suitability )
            {
                gentinfo = genp[i].info;
                genp[i].info = genp[j].info;
                genp[j].info = gentinfo;
                 
                gentsuitability = genp[i].suitability;
                genp[i].suitability = genp[j].suitability;
                genp[j].suitability = gentsuitability;      
            }
        }
    }
}

 
void cross()
{
    int i , j , k ;
    int mask1 , mask2;
    int a[SUM];
    for(i = 0 ; i < SUM ; i++)  a[i] = 0;
    k = 0;
    for(i = 0 ; i < SUM ; i++)
    {
        if( a[i] == 0)
        {
            for( ; ; )//随机找到一组未进行过交叉的染色体与a[i]交叉
            {
                j = randbit(i + 1 , SUM - 1);
                if( a[j] == 0)  break;
            }
            if(randsign(crossp) == 1)
            {
                mask1 = createmask(randbit(0 , 14));
                mask2 = ~mask1;
                gen_new[k].info = (gen_group[i].info) & mask1 + (gen_group[j].info) & mask2;
                gen_new[k+1].info=(gen_group[i].info) & mask2 + (gen_group[j].info) & mask1;
                k = k + 2;
            }
            else
            {
                gen_new[k].info=gen_group[i].info;
                gen_new[k+1].info=gen_group[j].info;
                k=k+2;
            }
            a[i] = a[j] = 1;
        }
    }
}

 
void selection()
{
    int i , j , k;
    j = 0;
    i = SUM/2-1;
    if(gen_group[i].suitability < gen_new[i].suitability)
    {
        for(j = 1 ; j < SUM / 2 ; j++)
        {
            if(gen_group[i+j].suitability > gen_new[i-j].suitability)
                break;
        }
    }
    else
        if(gen_group[i].suitability>gen_new[i].suitability)
        {
            for(j=-1;j>-SUM/2;j--)
            {
                if(gen_group[i+j].suitability<=gen_new[i-j].suitability)
                    break;
            }
        }
    for(k=j;k<SUM/2+1;k++)
    {
        gen_group[i+k].info = gen_new[i-k].info;
        gen_group[i+k].suitability = gen_new[i-k].suitability;
    }   
}

 
int record()
{
    float x;    
    struct log *r;
    r=(struct log *)malloc(sizeof(llog));
    if(r==NULL)
    {
        printf("\n内存不够!\n");
        exit(0);
    }
    r->next = NULL;
    end->suitability = gen_group[0].suitability;
    end->next = r;
    end = r;
    log_num++;

 
    x = gen_result.suitability - gen_group[0].suitability;
    if(x < 0)x = -x;
    if(x < error)
    {
        result_unchange_time++;
        if(result_unchange_time >= 20)return 1;
    }
    else
    {
        gen_result.info = gen_group[0].info;
        gen_result.suitability = gen_group[0].suitability;
        result_unchange_time=0;
    }
    return 0;
}

 
void mutation()
{
    int i , j , m;
    float x;
    float gmp;
    int gentinfo;
    float gentsuitability;
    gmp = 1 - pow(1 - mp , 11);//在基因变异概率为mp时整条染色体的变异概率
    for(i = 0 ; i < SUM ; i++)
    {
        if(randsign(gmp) == 1)
        {
            j = randbit(0 , 14);
            m = 1 << j;
            gen_group[i].info = gen_group[i].info^m;
            x = convertionB2D(gen_group[i].info);
            gen_group[i].suitability = x*(x*(x*(x*(x*(x-10)-26)+344)+193)-1846)-1680;
        }
    }
    for(i = 0 ; i < SUM - 1 ; i++)
    {
        for(j = i + 1 ; j < SUM ; j++)
        {
            if(gen_group[i].suitability > gen_group[j].suitability)
            {
                gentinfo = gen_group[i].info;
                gen_group[i].info = gen_group[j].info;
                gen_group[j].info = gentinfo;
                 
                gentsuitability = gen_group[i].suitability;
                gen_group[i].suitability = gen_group[j].suitability;
                gen_group[j].suitability = gentsuitability;
            }
        }
    }
}

 
void showresult(int flag)//显示搜索结果并释放内存
{
    int i , j;
    struct log *logprint,*logfree;
    FILE *logf;
    if(flag == 0)
        printf("已到最大搜索次数,搜索失败!");
    else
    {
        printf("当取值%f时表达式达到最小值为%f\n",convertionB2D(gen_result.info),gen_result.suitability);
        printf("收敛过程记录于文件log.txt");
        if((logf = fopen("log.txt" , "w+")) == NULL)
        {
            printf("Cannot create/open file");
            exit(1);
        }
        logprint=head;
        for(i = 0 ; i < log_num ; i = i + 5)//对收敛过程进行显示
        {
            for(j = 0 ; (j < 5) & ((i + j) < log_num-1) ; j++)
            {
                fprintf(logf , "%20f" , logprint->suitability);
                logprint=logprint->next;             
            }
            fprintf(logf,"\n\n");
        }
    }
    for(i = 0 ; i< log_num ; i++)//释放内存
    {
        logfree=head;
        head=head->next;
        free(logfree);
        fclose(logf);
    }
    getchar();
}

 
int randsign(float p)//按概率p返回1
{
    if(rand() > (p * 32768))
        return 0;
    else return 1;
}
int randbit(int i, int j)//产生在i与j之间的一个随机数
{
    int a , l;
    l = j - i + 1;
    a = i + rand() * l / 32768;
    return a;
}
int randnum()
{
    int x;
    x = rand() / 2;
    return x;
}
float convertionB2D(int x)
{
    float y;
    y = x;
    y = (y - 8192) / 1000;
    return y;
     
}
int convertionD2B(float x)
{
    int g;
    g = (x * 1000) + 8192;
    return g;
}
int createmask(int a)
{
    int mask;
    mask=(1 << (a + 1)) - 1;
    return mask;
}
搜索更多相关主题的帖子: include 如何 
2016-04-20 16:01
头大脑袋疼
Rank: 1
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回复 2楼 qq1023569223
有没有什么技巧?有时候关键字,语法之类的不会找  刚接触C#
2016-04-22 19:47
头大脑袋疼
Rank: 1
等 级:新手上路
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回复 3楼 over1230
我现在是有力无处使啊   没法下手
2016-04-22 19:48



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