************************************************************求X的Y次方******************************************************************************************
#include
int main(void)
{
        float x,n,result,a,sum=1;
        printf("TO:X**N\n");
        printf("PLEASE ENTER X,N.\n");
        scanf("%f,%f",&x,&n);
        printf("x=%f,n=%f\n",x,n);
        if(n==0)
{
        printf("result is 1\n");
}
      else
{
        for(a=0;a

<n;a++)
        sum=sum*n;
}
        printf("RESULE=%f\n",sum);
        return 0;
}

抄掉了 。。
不好意思

#include<stdio.h>
int main(void)
{
    float x,n,result,a,sum=1;
    printf("TO:X**N\n");
    printf("PLEASE ENTER X,N.\n");
    scanf("%f,%f",&x,&n);
    printf("x=%f,n=%f\n",x,n);
    if(n==0)
{
    printf("result is 1\n");
}
    if(n>0)
{
    for(a=0;a<n;a++)
    sum=sum*n;
}
    printf("RESULE=%f\n",sum);
    return 0;
}
*******************************************
root@localhost:~/programing/C_source# ./a.out
TO:X**N
PLEASE ENTER X,N.
2,3
x=2.000000,n=3.000000
RESULE=27.000000
结果不对
请问 错在那里？

谢谢 提醒