程序代码：

assume cs:code

 a segment
    db 1,2,3,4,5,6,7,8

 a ends

 b segment
    db 1,2,3,4,5,6,7,8

 b ends

 c segment
    db 0,0,0,0,0,0,0,0

 c ends
code segment
mov bx,0
mov cx,8
mov ax,a
mov ds,ax
mov ax,0
s:add al,[bx]
add al,[bx+8]
mov [bx+16],al
inc bx
loop s
mov ax,4c00h
int 21h
code ends
end start

意思是 把a+b的值存到c中

add al,[bx+8]
mov [bx+16],al
这两行有什么问题没