#include<stdio.h>
int main()
{
    int i,j,k=1,A[10],B[5],C[5],D[5];
    for(i=0;i<5;i++)
        scanf("%d",&A[i]);
    for(i=0;i<5;i++)
        B[i]=A[i+1]-A[i];
        C[i]=A[i+1]/A[i];
        D[i]=A[i]+A[i+2];
    for(i=0;i<4;i++)
        if(B[i]!=B[i+1])
        {
            break;
            k=0;
        }
        if(k==1)
            for(i=5;i<10;i++)
            {
                A[i]=A[i-1]+B[1];
                printf("%d",A[i]);
            }
        else if(k==0)
        {
            for(i=0;i<4;i++)
                if(C[i]!=C[i+1])
            {
                break;
                k=0;
            }
        }
        if(k==1)
            for(i=5;i<10;i++)
            {
                A[i]=A[i-1]*C[1];
                printf("%d",A[i]);
            }
        else if(k==0)
        {
            for(i=2,j=0;i<5;i++,j++)
                if(D[i]!=A[i])
                {
                    break;
                    k=0;
                }
        }
        if(k==1)
            for(i=5;i<10;i++)
            {
                A[i]=A[i-2]+A[i-1];
                printf("%d",A[i]);
            }
        else if(k==0)printf("NULL");
        return 0;
}



怎么回事啊？？

#include<stdio.h>
#include<string.h>
int main()
{
    int n,B[100],i,j=0,k=0,p,b;
    char A[4][4]={'West''South''East''North'},B[4];
    scanf("%s %d",&B,&n);
    for(i=0;i<4;i++)
        if(strcmp(A[i],B)==0)
        {
            b=i;
        }
    for(i=0;i<n;i++)
        scanf("%d",&B[i]);
    for(i=0;i<n;i++)
    {
        if(B[i]==0)
        {
            j++;
        }
        else if(B[i]==1)
        {
            k++;
        }
    }
    p=j-k;
    if(p>=4)
        p=P%4;
    b+=p;
    printf("%s",A[b]);
    return 0;
}

那咋简化一下啊？？

还有第二题呢？？大神。。。

这是第二题的题目，帮帮忙啊。。。