#include <iostream>
using namespace std;
int main()
{
    char* p1 = new char[10];
   
    char a[100] = "rbrbrr";
    a = p1;//    错误IntelliSense: expression must be a modifiable lvalue
    cout<<p1<<endl;
    cout<<a<<endl;
    system("pause");
    return 0;
}
求解，为什么同是char*类型，a不能被赋指针值？