请高手帮忙分析下哪里错了 ，下边的下拉菜单就是获取不到上边的下拉菜单的值，谢谢啦
<!--#include file=../conn/conn1.asp --><% if request.cookies("okadmin")="" and request.cookies("rank")="" then
response.redirect "login.asp"
end if %>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=gb2312">
<title>无标题文档</title>
<style type="text/css">
<!--
.unnamed1 {
font-size: 9pt;
}
-->
</style>
</head>
<body>
<div align="center">
<p>
<form name="myform" method="POST" action="tjnews_act.asp">
<table width="529" height="331" border="0" align="center" cellpadding="0" cellspacing="0">
<tr>
<td height="77" colspan="2"><div align="center"><u><b><font size="4">
添加客户详细信息</font></b></u></div></td>
</tr>
<tr>
<td height="29" colspan="2"><span style="font-size: 9pt">主机型号：
<%
sql="select * from building where cjyt='台式机主机' or cjyt='笔记本'"
set rs=server.createobject("ADODB.Recordset")
rs.open sql,conn,1,1
%>
<select name="jqxh" onChange="changelocation(document.myform.jqxh.options[document.myform.jqxh.selectedIndex].value)" size="1">
<option selected value="<%=trim(rs("name"))%>"><%=trim(rs("name"))%></option>
<%
seljqxh=rs("name")
rs.movenext
do while not rs.eof
%>
<option value="<%=trim(rs("name"))%>"><%=trim(rs("name"))%></option>
<%
rs.movenext
loop
rs.close
%>
</select>
</span></td>
</tr>
<tr>
<td height="29" colspan="2"><span style="font-size: 9pt">主机编码：
<select name="jqbm">
<option selected value="">请选择机器编码</option>
<%
sql2="select * from building where name='"&seljqxh&"' "
set rs2=server.createobject("ADODB.Recordset")
rs2.open sql2,conn,1,1
if not(rs2.eof and rs2.bof) then
%>
<option value="<%=rs2("who")%>"><%=rs2("who")%></option>
<%
do while not rs2.eof%>
<option value="<%=rs2("who")%>"><%=rs2("who")%></option>
<%
rs2.movenext
loop
end if
rs2.close
%>
</select>
</span></td>
</tr>
<tr>
<td height="48" colspan="2" valign="bottom">
<p align="center"><input type="submit" name="Submit" value="提 交">
<input type="reset" name="Submit2" value="重 填"></td>
</tr>
</table>
<p class="unnamed1"> </p>
</form>
</p>
</div>
</body>
</html>
