#include"stdio.h"
main()
{
    int n,a,i,b;
    char c;
    scanf("%d",&n);
    for(i=n;i>0;i--)
    {
        scanf("%c",&c);
        switch(c)
        {
            case'+':
            {
                scanf("%d %d",&a,&b);
                printf("%d\n",a+b);
                break;
            }
            case'-':
            {
                scanf("%d %d",&a,&b);
                printf("%d\n",a-b);
                break;
            }
            case'*':
            {
                scanf("%d %d",&a,&b);
                printf("%d\n",a*b);
                break;
            }
            case'/':
            {
                scanf("%d %d",&a,&b);
                printf("%.2f\n",(a*1.0)/b);
                break;
            }
        }   
    }
}

输入数据如下 为什么到第二次就结束了?
4
+ 1 2
- 1 2
* 1 2
/ 1 2

好像没什么效果哦。不过还是挺感谢的。。。

http://acm.hdu.
这样设计？为什么错？我实在搞不懂？求教求教
#include "stdio.h"
main()
{
    int n,a,i,b;
    char c;
    scanf("%d",&n);
    for(i=n;i>0;i--)
    {
        fflush(stdin);
        scanf("%c",&c);
        switch(c)
        {
            case'+':
            {
                scanf("%d %d",&a,&b);
                printf("%d\n",a+b);
                break;
            }
            case'-':
            {
                scanf("%d %d",&a,&b);
                printf("%d\n",a-b);
                break;
            }
            case'*':
            {
                scanf("%d %d",&a,&b);
                printf("%d\n",a*b);
                break;
            }
            case'/':
            {
                scanf("%d %d",&a,&b);
                printf("%.2f\n",(a*1.0)/b);
                break;
            }
            default:
                break;
        }   
    }
}

求这道题的解题思路。。。