这是我的程序#include "stdio.h"
void main()
{int number; char today[20];
    printf("please put the number:");
     scanf("%d",&number);
     switch(number)
     {case  1: today="monday";break;
      case  2: today="tuseday";break;
      case  3: today= "wendnesday";break;
      case  4: today="thursday";break;
      case  5: today="friday";break;
      case  6: today="saturday";break;
      case  7: today="sunday";break;
      default: today="no this day";};
     printf("%s",today);
   
}显示有错误

这是别人帮我改的#include "stdio.h"
void main()
{int number; char today[20],*p=today;
     printf("please put the number:");
      scanf("%d",&number);
      switch(number)
      {case   1:p="monday";break;
       case   2:p="tuseday";break;
       case   3:p="wendnesday";break;
       case   4:p="thursday";break;
       case   5:p="friday";break;
       case   6:p="saturday";break;
       case   7:p="sunday";break;
       default:p="no this day";};
       printf("%s\n",p);
     
}是正确的 额 我想问 为什么需要*p=taday 这一步 为什么这里的p不能直接用today代替