大家看看为什么最后的i=1，j=11
int main(){int i=10;
int j=11;
if((i=0)&&(j=0)){
printf("(i=0)&&(j=0)operation is true .\n");}
else{printf("(i=0)&&(j=0)operation is false.\n");}
printf("i=[%d],j=[%d]\n",i,j]);
i=10;
j=11;
if((i=1)&&(j=1)){
printf("(i=1)&&(j=1)operation is true .\n");}
else{printf("(i=1)&&(j=1)operation is false.\n");}
printf("i=[%d],j=[%d]\n",i,j]);
return 0;
}
