using System.Diagnostics;

using System.Reflection;

public static Process RunningInstance()

{

Process current = Process.GetCurrentProcess();

Process[] processes = Process.GetProcessesByName(current.ProcessName);

//Loop through the running processes in with the same name

foreach (Process process in processes)

{

//Ignore the current process

if (process.Id != current.Id)

{

//Make sure that the process is running from the exe file.

if (Assembly.GetExecutingAssembly().Location.Replace("/", "\\") == current.MainModule.FileName)

{

//Return the other process instance.

return process;

}

}

}

//No other instance was found, return null.

return null;

}

系统Main函数
if( RunningInstance() == null )

Application.Run(new yourFormName());

我用上面这种方法让程序只能产生一个实例，
我想做的是：如果程序已经运行，把它弹出并显示到最前面。

怎么实现 望高手指点！