//一个数如果恰好等于它的因子之和，这个数就称为“完数”；输出1000内的所有完数；



#include <iostream>
using std::cout;
using std::cin;
using std::endl;


int main()
{
    int a,top,sum,n,count;

    top=1000;
    sum=0;
    
    for(a=2;a<=top;a++)
    {
        for(n=1;n<a;n++)
        {
            if(a%n==0)
                sum=sum+n;
        }
    }

    if(sum==a)
    {
        cout<<sum<<"its farctors are ";
        for(count=1;count<a;count++)
        {
            if(sum%count==0)
                cout<<count<<","<<;
        }
    }
    return 0;

}
输出不来数，直接就是press any key to continue;
请帮找下毛病

嗯，谢谢了……我一见嵌套脑子就混乱……

看看这个，在VC6.0上试试，我快吓挂了……
#include <iostream>
using std::cout;
using std::cin;
using std::endl;
int main()
{
    int top,sum,n,count,a;
    top=1000;
    

    for(n=1;n<1000;n++)
    {
        sum=0;
        for(count=1;count<n;count++)
            n%count==0;
            sum+=count;
    

        if(sum==n)
        {
            cout<<sum<<" its factors are ";
            for(a=1;a<sum;a++)
            {
                if(sum%a==0)
                    cout<<a;
            }
        }
    }
    return 0;
}

//经过仔细的修改,终于……
//完数:
//例如:6=1+2+3;其中1,2,3是它的所有的因子(除6本身),并且6等于它的所有因//子数的和(除它本身)
#include <iostream>
using std::cout;
using std::cin;
using std::endl;
int main()
{
    int top,sum,n,count,a;
    top=1000;
    

    for(n=1;n<1000;n++)
    {
        sum=0;
        for(count=1;count<n;count++)
        {
            if(n%count==0)
            sum+=count;
        }
        
    

        if(sum==n)                
        {
            cout<<n<<" its factors are ";
            for(a=1;a<n;a++)
            {
                if(n%a==0)
                    cout<<a<<",";
            }
            cout<<endl;
        }
    }
    return 0;
}

            
在此谢谢大家对我的无私帮助