4位数猜测，不对就给出提示A表示位置和数字都对，B表示数字对位置不对

在线等答案






#include <math.h>
#include <stdio.h>
void main(void)
{
int answer[4]={1,3,5,2},guess,a,b,times=0,i,j;    /*初始化被猜答案为1352*/
printf("please guess\n");
while(a!=4)
{                                                 /*进入猜数字循环*/
a=0;
b=0;
times++;                                          /*猜测次数加1*/
printf("%d",times);                               /*显示猜测次数*/
scanf("%d",&guess);                               /*数取玩家输入数字*/
for(i=3;i>-1;i--)
{                                                 /*开始循环*/
for(j=0;j<4;j++)
{
if((int)(guess/pow10(i))==answer[j])
if(i+j==3)                                        /*如果位置相同A加1*/
a=a+1;
else
b=b+1;                                            /*如果位置不同B加1*/
}
}
guess=guess-(int)(guess/pow10(i)*pow10(i)
}                                                 /*对比下一位猜测数字*/
printf("%dA%dB\n",a,b);                           /*显示本次猜测AB正确性*/
}


谢谢先

大哥，错的啊，无法编译

#include <math.h>
#include <stdio.h>
void main(void)
{
int answer[4]={1,3,5,2},guess,a,b,times=0,i,j;    /*初始化被猜答案为1352*/
printf("please guess\n");
while(a!=4)
{                                                 /*进入猜数字循环*/
a=0;
b=0;
times++;                                          /*猜测次数加1*/
printf("%d",times);                               /*显示猜测次数*/
scanf("%d",&guess);                               /*数取玩家输入数字*/
for(i=3;i>-1;i--)
{                                                 /*开始循环*/
for(j=0;j<4;j++)
{
if((int)(guess/pow10(i))==answer[j])
if(i+j==3)                                        /*如果位置相同A加1*/
a=a+1;
else
b=b+1;                                            /*如果位置不同B加1*/
}
}
guess=guess-(int)(guess/pow10(i))*pow10(i);
}                                                 /*对比下一位猜测数字*/
printf("%dA%dB\n",a,b);                           /*显示本次猜测AB正确性*/
}



我的我修改了，但是和你有同样的问题就是死循环，今天搞定，

是啊，正在修改当中，新人嘛！