下面是求编码函数，为什么用#if 0和endif 之间的代码替换静态数组就不行呢？用静态数组可以求的结果，怎么要是改成动态char **c这种形式程序就死啊，退不出来啊！


static void Coding(Huffman T[], int N)
{
char c[20][20] = {'\0'};
int i, j, k, step, father;

#if 0
char **c;
if (((c = (char**)malloc(sizeof(char*) * N))) == NULL)
{
exit(1);
}

for (i = 0; i < N; i++)
{
if (((c[i] = (char*)malloc(sizeof(char) * (N + 1)))) == NULL)
{
exit(1);
}
}

for (i = 0; i < N; i++)
{
for (j = 0; j < N + 1; j++)
{
c[i][j] = '\0';
}
}
#endif

for (i = 0; i < N; i++) /* get every node code */
{
step = i, k = 0;
father = T[step].parent;

while (father != -1)
{
if (T[father].lchild == step)
{
c[i][k++] = '0';
}
else
{
c[i][k++] = '1';
}

step = father;
father = T[step].parent;
}
}

printf("The Coding Is:\n");
for (j = 0; j < N; j++)
{
printf("%s\n", c[j]);
}
}