怎么才能在屏幕上用循环结构完成"九九表"的功能




一个嵌套循环
numberA db 0 ;乘数
numberB db 0 ;被乘数
mov ax,0
mov cl,10
againA:
inc numberA
cmp cl,numberA
jz exit
againB:
inc numberB
cmp cl,numberB
jz againA
print:
mov al,numberA
add al,30h
mov dl,al
mov ah,2
int 21h ;print numberA
mov dl,'*'
mov ah,2
int 21h ;print '*'
mov al,numberB
add al,30h
mov dl,al
mov ah,2
int 21h ;print numberB
mov dl,'='
mov ah,2
int 21h ;print '='
call printNum ;print product ,to pass over the procedure.
mov dl,','
mov ah,2
int 21h
jmp againB
[此贴子已经被作者于2006-5-22 12:12:25编辑过]
一个嵌套循环
numberA db 0 ;乘数
numberB db 0 ;被乘数
mov ax,0
mov cl,10
againA:
inc numberA
cmp cl,numberA
jz exit; 这是什么意思?
againB:
inc numberB
cmp cl,numberB
jz againA
print:
mov al,numberA
add al,30h
mov dl,al
mov ah,2
int 21h ;print numberA
mov dl,'*'
mov ah,2
int 21h ;print '*'
mov al,numberB
add al,30h
mov dl,al
mov ah,2
int 21h ;print numberB
mov dl,'='
mov ah,2
int 21h ;print '='
call printNum ;print product ,to pass over the procedure.;本程序中没有编写printNum子程序,怎么调用程序?
mov dl,','
mov ah,2
int 21h
jmp againB
嵌套循环里,numberA作为外层循环哨兵,numberB作为内层循环哨兵,cmp cl,numberA 乘数等于10 转exit退出,程序里我没有给出exit,显然exit是跟在上面代码最后面、那个打印乘积的部分我都说了省略嘛,其实就是打印乘积,因为要把两位数打印有点麻烦,所以我没有完全实现这个代码,你可以参考我在kill444的“课程设计”帖子里写的子程序、