程序代码:
#include <stdio.h>
int main()
{
double dx = 1, dy = 1, n = 0;
double d = 1, sum = 1;
while (d >= 1e-6)
{
dx *= ++n;
dy *= (2 * n + 1);
d = dx / dy;
sum += d;
}
sum *= 2;
printf("%lf", sum);
return 0;
}


