二进制转换任意进制，有点问题 求助
程序代码：#include<stdio.h>
#include<string.h>
int two_to_ten(char *p,int n)
{
int sum = 0;
for(int i = 0;i<n;i++)
{
sum *= 2 ;
sum += p[i] - '0';
}
return sum;
}
void ten_to_any(int n, int change,char * buf)
{
char bbq[128] = {0};
int count =0 ;
while(1)
{
bbq[count] = n % change ;
count++;
n=n/change;
if(bbq[count] >= 0 && bbq[count] <= 9)
{
bbq[count] = bbq[count] +'0';
}
else
bbq[count] = bbq[count] + 'A'-10;
if(n==0) break;
}
for(int i =0;i<count;i++)
buf[i]=bbq[count-i-1];
}
int main()
{
char buf[128]={0};
printf("Please input a two_:\n");
gets(buf);
int n = two_to_ten(buf,strlen(buf));
printf("转换的十进制为%d\n",n);
char buf1[128] = {0};
int x = 0;
printf("请输入要转换的进制:\n");
scanf("%d",&x);
ten_to_any(n,x,buf1);
puts(buf1);
return 0;
}这是代码 二进制先转换成10进制 10进制在求余数 取反， 十转任意会出现乱码， 求解？
