int main()

 {   
     double disgusting[3][4][5][6] = {{{{0}}}};  
     double (*ptr)[6] = _____;  
     ptr[2][3] = 2.3333;   
     return 0; } 

Which of the following expressions would be correct to fill in the blank?
A. disgusting[0]
 B. disgusting[2][1]
C. (double *[6])disgusting[4][3]
D. disgusting[0][3][2]

答案是B

把disgusting[3][4]看成数组名是不是就选出来B了

不知道，这是解析，没看懂
Explanation: disgusting[2][1] is of type double [5][6] , thus implicitly-convertible to type double (*)[6] . disgusting[0] is of type double [4][5][6] , convertible to type double (*)[5][6] .
double *[6] is a type for an array of six elements whose type is double * , and is different than double (*)[6] , a pointer to type double [6]
disgusting[0][3][2] is of type double [6] , convertible to type double * .

double (*ptr)[6]声明了一个指向二维数组的指针，要传它一个二维数组的地址。所以是B啊。

哦哦，理解了。谢谢啦！