//带有参数的main()函数
#include<stdio.h>
int main(int argc, char *argv[])
{
    int count;
    printf("The command line has %s arguments:\n", argc - 1);
    for (count = 1;count < argc;count++)
        printf("%d: %s\n", count, argv[count]);
    printf("\n");

    system("pause");
    return 0;
}

如题，谢谢！

我把程序放在桌面的test文件夹中

printf("The command line has %s arguments:\n", argc - 1);
改为：
printf("The command line has %d arguments:\n", argc - 1);

谢谢！

谢谢！

请问这个怎么回事呐？下面是代码，在命令行运行就这样，我是完全不懂，谢谢

//把命令行参数转换成数字
#include<stdio.h>
#include<stdlib.h>

int main(int argc, char *argv[])
{
    int i, times;

    if (argc < 2 || (times = atoi(argv[1])) < 1)
        printf("Usage:%s positive-number\n", argv[0]);
    else
        for (i = 0;i < times;i++)
            puts("Hello,good looking!");

    system("pause");
    return 0;
}

确保路径正确

看6楼的图片，路径我是直接复制的，前面多一个？