是啊 还有一个星期就到龙年了

梅尚程荀
马谭杨奚
2012-01-15 19:51

2012-01-15 20:02

2012-01-15 20:49
2012-01-15 20:50
2012-01-15 21:40
我提供一种方法,大家积极贴代码啊
程序代码:#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <windows.h>
#define N 101
int main(int argc, char *argv[])
{
int n = 1, i, j, k;
int a1[N], a2[N];
printf("input\toutput\n");
while (n <= 50)
{
printf("%d\t", n);
for (i = 0; i <= n; i++)
{
a1[i] = 1;
a2[i] = 0;
}
for (i = 2; i <= n; i++)
{
for (j = 0; j <= n; j++)
for (k = 0; k + j <= n; k += i)
a2[k + j] += a1[j];
for (j = 0; j <= n; j++)
{
a1[j] = a2[j];
a2[j] = 0;
}
}
printf("%d\n", a1[n]);
n++;
if (n % 23 == 0)
system("pause");
}
return 0;
}。
2012-01-16 13:35

2012-01-16 14:39

2012-01-16 17:02
2012-01-16 17:05

2012-01-16 17:07