大家看看这个程序哪里有错误，还有没有更简洁效率更高的程序？
#include<stdio.h>
void main()
{
    int i,j,k;
    for(i=0;i<=9;i++)
    {
        if((i+5)%3==0)
        {
            printf("%3d %3d",i*10+5,50+i);
            k+=2;
            if(k%4==0)
                printf("\n");
        }
        for(j=0;j<=9;j++)
        {
            if((i+j+5)%3==0)
            {
                if(i!=j)
                {
                    if((i!=5)&&(j!=5))
                    {
                        printf("%3d %3d ",500+10*i+j,500+10*j+i);
                        k+=2;
                        if(k%4==0)
                            printf("\n");
                        else
                        {
                            printf("%3d %3d ",100*i+10*j+5,100*i+50+j);
                            k+=2;
                        }
                        if(k%4==0)
                            printf("\n");
                        else
                        {
                            printf("%3d %3d ",100*j+10*i+5,100*j+50+i);
                            k+=2;
                        }
                        if(k%4==0)
                            printf("\n");
                    }
                    if(i==5)
                    {
                        if(k%4==1||k%4==0)
                        {
                            printf("%3d %3d %3d ",550+i,505+10*i,100*i+55);
                            k+=3;
                            if(k%4==0)
                                printf("\n");
                        }
                        else
                        {
                            if(k%4==2)
                            {
                                printf("%3d %3d \n%3d ",550+i,505+10*i,100*i+55);
                                k+=3;
                            }
                            else
                            {
                                if(k%4==3)
                                {
                                    printf("%3d \n%3d %3d ",550+i,505+10*i,100*i+55);
                                    k+=3;
                                }
                                
                        }
                    }
                    if(j==5)
                    {}
                }
                if(i==j&&i!=5)
                {
                    if(k%4==1||k%4==0)
                    {
                        printf("%3d %3d %3d ",500+10*i+i,100*i+50+i,100*i+10*i+5);
                        k+=3;
                        if(k%4==0)
                                printf("\n");

                    }
                    else
                    {
                        if(k%4==2)
                        {
                            printf("%3d %3d \n%3d ",500+10*i+i,100*i+50+i,100*i+10*i+5);
                            k+=3;
                        }
                        else
                        {
                            printf("%3d \n%3d %3d ",500+10*i+i,100*i+50+i,100*i+10*i+5);
                            k+=3;
                        }
                    }

                }
                if(i==j&&i==5)
                printf("%3d ",555);

            }            

        }
    }
}

确实写的比较长，估计三分之一的代码就足足有余了。最笨的方法就是从3开始，增量为3，再判断该数，若其某位含有3即是符合条件的。

#include <stdio.h>

int main()
{
    int n;
    for (n=3; n<1000; n+=3)
    {
        if (n%10==3 || n/10%10==3 || n/100==3)
            printf("%d,", n);
    }
    return 0;
}

#include <stdio.h>

int main()
{
    int n, c=0;
    for (n=3; n<1000; n+=3)
    {
        if (n%10==3 || n/10%10==3 || n/100==3)
        {
            printf("%d ", n);
            if (++c>=4)
                puts(""), c=0;
        }
    }
    return 0;
}

4个一行的话

3的倍数也就是各个位数的和能整除3

设个 char a,b,c;
a=3;
0<=b<10,0<=c<10;
那么只需(b+c)%3==0
然后 a,b,c组合  

御姐的回帖一定要顶，

不带你这样玩的,这样更累

一个数除10的余就是他的个位数,
还是这招if (n%10==3 || n/10%10==3 || n/100==3)
高

#include <stdio.h>

int main()
{
    int n, c=0;
    for (n=1; n<1000; n++)
    {
        if( (n%3==0)&&( (n%10==3 || n/10%10==3 || n/100==3)))
        {
            printf("%d ", n);
            if (++c>=4)
                puts(""), c=0;
        }
    }
    return 0;
}
拿御姐的改一下,别生气哦

我知道你们那样会比较短，但我的那个效率会更高的啊