#include<stdio.h>
#include<math.h>
void main()
{

int j,n,x;

float sum=0.0;
int term=1;
n=32;
printf("请输入x\n");
scanf("%d",&x);
for(j=0;j<=n;++j)
{
term=term*x/j;
sum=sum+term;
if(term<=1e-8)
break;
}
printf("e的x次幂=%f\n",sum);
}

那怎么求e的x次幂