1现在是这样的<INPUT name=text11 value=<%=rs("邮箱")%>>

2如何判断读出字符穿里有'@'就是 如何判断邮箱的添写

3如何判断读出字符的第几位是什么

4下面是一段在添加时判断是否有重复的 代码 可是总是提是出错.现在我注释掉了 判断的语句就可以运行了 但还是想知道 为什么着样就运行不了 要改的话 应该怎么改呢??
set rs=server.createobject("adodb.recordset")
set rs1=server.createobject("adodb.recordset")

conn = "DBQ=" + server.mappath("address.mdb") + ";DefaultDir=;DRIVER={Microsoft Access Driver (*.mdb)};"

sql1="select * from 专家联络方式 where 联系人='"&lianxiren&"'"

rs1.Open sql1,conn,1,1

if rs.EOF or rs.bof then
sql="...添加语句..."
rs.Open sql,conn,1,1 （着句忘了加上了）
response.write "<script language=JavaScript>" & chr(13) & "alert('添加成功！');" & "history.back()" & "</script>
set rs=nothing
end if
else
response.write "<script language=JavaScript>" & chr(13) & "alert('此信息已添加！');" & "history.back()" & "</script>
end if
rs1.Close
set rs1=nothing

[此贴子已经被作者于2007-5-22 15:18:43编辑过]

自己顶下吧 都没人理我~

set rs=server.createobject("adodb.recordset")
set rs1=server.createobject("adodb.recordset")

conn = "DBQ=" + server.mappath("address.mdb") + ";DefaultDir=;DRIVER={Microsoft Access Driver (*.mdb)};"

sql1="select * from 专家联络方式 where 联系人='"&lianxiren&"'"

rs1.Open sql1,conn,1,1

if rs1.EOF then
sql="...添加语句..."
response.write "<script language=JavaScript>" & chr(13) & "alert('添加成功！');" & "history.back()" & "</script>
else
response.write "<script language=JavaScript>" & chr(13) & "alert('此信息已添加！');" & "history.back()" & "</script>
end if
rs1.Close
set rs1=nothing

看看可不可以

if rs.EOF or rs.bof then
sql="...添加语句..."
response.write "<script language=JavaScript>" & chr(13) & "alert('添加成功！');" & "history.back()" & "</script>
set rs=nothing
end if去掉
else
response.write "<script language=JavaScript>" & chr(13) & "alert('此信息已添加！');" & "history.back()" & "</script>
end if
rs1.Close
set rs1=nothing

前几个问题 也说下啊 呵呵