要求用赋值语句，把个位和万位互换，十位和千位互换，哪位把代码给我，谢了！

要用C语言编程，谁来解决一下？

main()
{long i,j,m,n;
long a,num;
scanf("%ld",&a);
i=a/10000;
j=a/1000%10;
m=a%10;
n=a/10%10;
num=m*10000+n*1000+(a/100%10)*100+j*10+i;
printf("your input number is %ld\nafter changed the number is %ld\n",a,num);
getch();
}

或者这个
main()
{long a;
scanf("%ld",&a);
printf("your input number is %ld\nafter changed the number is %ld\n",a,a%10*10000+a/10%10*1000+a/100%10*100+a/1000%10*10+a/10000);
getch();
}

[此贴子已经被作者于2006-11-4 16:28:11编辑过]

main()
{long a,i=5,array[5];
scanf("%ld",&a);
for(i=0;i<5;i++)
{
array[i]=a%10;
a=a/10;
if(a==0)
break;
}
for(i=0;i<5;i++)
printf("%d",array[i]);
getch();
}

[此贴子已经被作者于2006-11-4 16:49:51编辑过]

#include<stdlib.h>
main()
{
int i;
char N_Char[6],t;
long num;

scanf("%ld",&num);
ltoa(num,N_Char,10);
for(i=0;i<2;i++)
{
t=N_Char[i];
N_Char[i]=N_Char[4-i];
N_Char[4-i]=t;
}
num=atof(N_Char);
printf("%ld",num);
getch();
}

num=num-num/10000*10000+num/10000+num%10*10000-num%10; //5和1换

num=num-(num/1000%10*1000)+(num/10%10*1000)-(num/10%10*10)+(num/1000%10*10)//4和2换
printf(num);

好在位数不多，多了手尾长。

的确如此
当然也可以这样
long sum=0;
while(num)
{
sum=sum*10+num%10;
num/=10;
}
printf("%ld\n",sum);