#include <stdio.h>
 int QUFAN(int x,int t)
 {
     t=((x)>=0?(x):-(x));
         return t;
 }
mian()
{
    int x,y,t,q;
x=-5;
y=-5;
q=0;
t=0;
for(y=-5;y<=5;y++)
{
    for(x=-5;x<=5;x++)
    {
        t=QUFAN(x,t);
        q=QUFAN(y,q);
        if(t+q<=10)
            printf("*");
        else printf(" ");
    }
    printf("\n");
}
}

[此贴子已经被作者于2016-11-16 21:01编辑过]

#include <stdio.h>
#include <stdlib.h>
int main()
{
    unsigned n;
    scanf("%u",&n);
    char *p=(char *)malloc(sizeof(char)*(n+1));
    for(int i=0;i<n;++i) p[i]='*';
    p[n]=0;
    for(int i=0;i<n;++i)
    {
        if(i==0||i==n-1) printf("%s\n",p);
        else printf("%c%*c\n",p[0],n-1,p[0]);
    }
    free(p);
     return 0;
}

链表吗？我还没看完那部分的知识0.0

不过还是谢谢你

不是链表，malloc开辟空间

好像不是链表0.0学艺不精啊，还得多看书

0.0还没学到...尴尬，想做一个跳动的心，又不想看源代码...慢慢来，谢谢你

我已经成功写出跳动的心了

#include <stdio.h>
int QUFAN(int x)
{
    return (x) >= 0 ? (x) : -(x);
}
main()
{
    int x, y, t, q;
    x = -5;
    y = -5;
    q = 0;
    t = 0;
    for (y = -5; y <= 5; y++)
    {
        if (y == 0) {
            continue;
        }
        for (x = -5; x <= 5; x++)
        {
            if(x == 0) {
                continue;
            }

            t = QUFAN(x);
            q = QUFAN(y);
            if (t + q <= 10)
                printf("*");
            else
                printf(" ");
        }
        printf("\n");
    }
}
1、mian --> main;
2、考虑 x,y = 0 的情况,否则会出现11行或11列