Description
Your task is to Calculate the sum of some integers.
Input
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.
Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
Sample Input
4 1 2 3 4
5 1 2 3 4 5
0
Sample Output
10
15

/*你参考下，对不对就不知道了，毕竟英文学的不咋地*/
#include <stdio.h>
#define M 10        //数组不够大，改这里就好了。
int main()
{
    int sum[M],n,k=0;
    for(int i=0;i<M;++i)
        sum[i]=0;
    while(scanf("%d",&n)&&n!=0&&k<M)
    {
        for(int i=0;i<n;++i)
        {
            int l;
            scanf("%d",&l);
            sum[k]+=l;
        }
        ++k;
    }
    for(int i=0;i<k;++i)
        printf("%d\n",sum[i]);
    return 0;
}

程序是错误的

错在哪了？

#include<stdio.h>
int main()
{
    int n,i,sum;
    int a[100];
    while(~scanf("%d",&n))
    {
        sum=0;
        if(n==0)
        return 0;
        else
        {
            for(i=0;i<n;i++)
    {
    scanf("%d",&a[i]);
    sum+=a[i];
     }
     printf("%d\n",sum);
    }
        }
    return 0;
 }
/*应该可以吧 你试试*/

[此贴子已经被作者于2017-2-12 18:17编辑过]