import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner cin = new Scanner(System.in);
        int n;
        while (cin.hasNext()) {
            n = cin.nextInt();
            long a[] = new long[n + 1];
            for (int i = 1; i <= n; i++) {

                a[i] = cin.nextInt();
            }
            Arrays.sort(a);
            for (int j = 1; j <= n; j++) {
                System.out.print(a[j] + " ");
                if (j % 100 == 0) {
                    System.out.println();
                    continue;
                } else {
                    continue;
                }
            }
            System.out.println();
        }
    }
}
这样不行吗？？？

continue;去掉

没有continue 也输不出、、、、

  long a[] = new long[201];
                for (int i = 0; i <= 200; i++) {

                    a[i] = i+1;
                }
              

                Arrays.sort(a);
                for (int j = 0; j <= 200; j++) {
                    System.out.print(a[j] + " ");
                    if (a[j]%100==0 ) {
                        System.out.println();
                    }

                }
                System.out.println();

自己看着改

import java.util.*;

public class Main {
    public static void main(String[] args) {
        Scanner cin = new Scanner(System.in);
        int n;
        while (cin.hasNext()) {
            n = cin.nextInt();
            long a[] = new long[n + 1];
            for (int i = 1; i <= n; i++) {

                a[i] = cin.nextInt();
            }
            Arrays.sort(a);
            for (int j = 1; j <= n; j++)
        if(j%100==0) System.out.print(a[j]+"\n");
        else System.out.print(a[j]);
        }
        cin.close();
    }
}

谢谢、、、问题已解决。

continue留着应该也可以吧，作用是直接跳回到for()这一句，
虽然for自动会跳转