#include "my.h"
char course[N][20];
void dispnode(Student *p)
{
   
    int i;
    printf("\n\nData for the student:\n");
    printf("number is %ld\tname is %s\n",p->number,p->name);
    printf("%d course scores are:\n",N);
    for(i=0;i<N;i++)
        printf("%s\t%d\n",course[i],p->score[i]);

}

谁可以帮我一下，把这段代码换另一种方法写出来