#include<stdio.h>
int main(void)
{
    int n,i,s=0;
    while(scanf("%d",&n)!=EOF&&n!=0){
        for(i=1;i<=n;i++){
            printf("%d",i);
            s=s+i;
        }
        printf("\n");
        printf("%d\n",s);
        s=0;
    }
    return 0;
}
为啥输入一个数后会自动换行

#include<stdio.h>
int main(void)
{
    int n,i,s=0;
    while(scanf("%d",&n)!=EOF&&n!=0){
        for(i=1;i<=n;i++){
            printf("%d",i);
            s=s+i;
        }
        printf("\n");
        printf("%d ",s);
        s=0;
    }
    return 0;
}
ok

scanf("%d",&n)!=EOF&&n!=0

EOF的值是-1, 应该使用

scanf("%d",&n)>0&&n>0 吧?

[ 本帖最后由 share32 于 2012-3-8 11:21 编辑 ]

抱歉，没表达清楚，scanf之后不自动换行，不是下次输入，好像不行哦