标题:求大虾指导指导!
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hk327143206
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求大虾指导指导!
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<malloc.h>
#define LEN 8           
#define MAXLEAF 8      // 最大叶子结点数目
#define MAXNODE (MAXLEAF*2)-1

typedef int ElemType;
typedef struct         /* this structure stores the information of code  */
{
    int start;           /* 存放编码的起始位置右至左(高位至低位)*/
    int bit[LEN];     /* 存放 huffman编码 */
}HCode;

typedef HCode HuffCode[MAXLEAF];
typedef struct       /* huffman tree结点的结构 */
{
    int parent;
    int LChild;
    int RChild;
    ElemType weight;
}HNode;

typedef HNode Huffman[MAXLEAF*2-1];

void createHuffmanTree(Huffman h,int leaves,ElemType *weight)
{
    int i,j;
    for(i=0;i<leaves*2-1;i++)    /* 初始化huffman tree */
    {
        (h+i)->parent=-1;
        (h+i)->LChild=-1;
        (h+i)->RChild=-1;
        (h+i)->weight=0;
    }
    for(i=0;i<leaves;i++)    /* 给叶子赋权重 */  
    {
        (h+i)->weight=*(weight+i);
    }
    /* 上一个循环叶子已经带权,下面这个循环用来生成新根
    *   新根数量为n-1
    */
    for(i=0;i<leaves-1;i++)  
    {
         ElemType m1, m2;
         int m1_pos, m2_pos;
         m1=m2=65536; /* m1存放最小的权值m2存放次小的权值 */
         m1_pos=m2_pos=0; /* m1存放最小的权值对应下标m2存放次小的权值对应下标*/

         for(j=0;j<leaves+i;j++)
         {

              if((h+j)->weight<m1&&(h+j)->parent==-1)
              {
                  m2=m1;
                  m1=(h+j)->weight;
                  m2_pos=m1_pos;
                  m1_pos=j;
              }
   
              
              else if((h+j)->weight<m2&&(h+j)->parent==-1)
              {
                  m2=(h+j)->weight;
                  m2_pos=j;
              }
         }
         (h+leaves+i)->parent=-1;       // 生成新根,无双亲-1
         (h+leaves+i)->LChild=m1_pos;  // 新根左孩子在数组中的下标
         (h+leaves+i)->RChild=m2_pos;  // 新根右孩子在数组中的下标
         (h+m1_pos)->parent=leaves+i;  // 原根的父亲位置
         (h+m2_pos)->parent=leaves+i;  // 原根的父亲位置

         (h+leaves+i)->weight=m2+m1;     
    }
}

void huffmancode(Huffman h,HuffCode code,int leaves)
{
    int i,j,p,c;
    HCode hf;
    /*从叶子结点开始向上回溯 从而计算出huffman code */
    for(i=0;i<leaves;i++)
    {
        c=i;
        p=h[i].parent;
        hf.start=LEN-1;
        while(p!=-1)
        {
            if(h[p].LChild==c)   
            {                    
                hf.bit[hf.start]=1;
            }
            else
            {
                hf.bit[hf.start]=0;
            }
            --hf.start;
            c=p;
            p=h[c].parent;
        }
        for(j=hf.start+1;j<LEN;j++)
        {
            code[i].bit[j]=hf.bit[j];
        }
        code[i].start=hf.start+1;
    }
        printf(    "%d",h[leaves-1].parent);
}

void printhuffcode(HuffCode hcode,char characters[],int weights[])
{
    int i,j;
    for(i=0;i<strlen(characters);i++)
    {
       // printf("%f的huffman编码:",characters[i]);
         printf("第%d个字符 "  ,i+1);
         printf("频率为%d对应的Huffman编码为:",weights[i]);
        for(j=hcode[i].start;j<LEN;j++)
        {
            printf("%d",hcode[i].bit[j]);
        }
        printf("\n");   
    }
}

void main()
{
    Huffman h;
    int i,q,k[6]={0},j,p=0;
    HuffCode hcode;
    char characters[]={"abcdef"},a[81],b[81];  /* 待编码的字符 */
    int weights[6];/* 字符出现的频率 */
    printf("请输入字符串:");
    gets(a);
    for(i=0;a[i]!='\0';i++)
    {
        if(a[i]=='a')k[0]++;
        else if(a[i]=='b')k[1]++;
        else if(a[i]=='c')k[2]++;
        else if(a[i]=='d')k[3]++;
        else if(a[i]=='e')k[4]++;
        else if(a[i]=='f')k[5]++;
        else q++;
    }
   // printf("请输入对应字符的发生频率:\n");
    for (i=0;i<6;i++)
       weights[i]=k[i];
    createHuffmanTree(h,strlen(characters),weights);
    huffmancode(h,hcode,sizeof(characters));
    printhuffcode(hcode,characters,weights);
   // system("pause");
    printf("请输出压缩的编码:");
    for(i=0;a[i]!='\0';i++)
    {
        if(a[i]=='a')
            for(j=hcode[0].start;j<LEN;j++)
        {
            printf("%d",hcode[0].bit[j]);
        }
        else if(a[i]=='b')
            for(j=hcode[1].start;j<LEN;j++)
        {
            printf("%d",hcode[1].bit[j]);
        }
        else if(a[i]=='c')
            for(j=hcode[2].start;j<LEN;j++)
        {
            printf("%d",hcode[2].bit[j]);
        }
        else if(a[i]=='d')
            for(j=hcode[3].start;j<LEN;j++)
        {
            printf("%d",hcode[3].bit[j]);
        }
        else if(a[i]=='e')
            for(j=hcode[4].start;j<LEN;j++)
        {
            printf("%d",hcode[4].bit[j]);
        }
        else if(a[i]=='f')
            for(j=hcode[5].start;j<LEN;j++)
        {
            printf("%d",hcode[5].bit[j]);
        }
        else q++;
    }   
   /*    printf("请输入需要解压的的编码:");
    gets(b);
    for(i=0;b[i]!='\0';i++)p++;
    for(i=p-1;i>=0;i--)
    {*/
}
帮忙在后面写个解压编码的过程!这是哈夫曼编码的解压过程,比如输入010010101001110101010则输出abcdef中的字母

搜索更多相关主题的帖子: 叶子 structure include start 
2011-11-29 02:03
hk327143206
Rank: 2
等 级:论坛游民
帖 子:35
专家分:31
注 册:2011-6-25
得分:0 
怎么没人帮我啊?
2011-12-01 00:02



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