题目：在一次会议上，Ａ说Ｂ在说假话，Ｂ说Ｃ在说假话，Ｃ说Ａ和Ｂ在说假话。试问谁在说假话，谁在说真话。

我程序如下不知道哪出错了它好像只执行一次循环
/*判断谁在说真话谁在说假话*/
#include <stdio.h>

int main()
{
    int A;
    int B;
    int C;
    int count = 0;
   
    for (A=0; A<2; A++)
    {
        for (B=0; B<2; B++)
        {
            for (C=0; C<2; C++)
            {
                count += ((A == 1 && B == 0) || (A == 0 && B ==1));
                count += ((B == 1 && C == 0) || (B == 0 && C == 1));
                count += ((C == 1 && A == 0 && B == 0) || (C == 0 && A == 1 && B== 1));
                goto finish;
            }
        }
    }
   
    finish : if (count == 3)
         {
             printf("A is saying %s.word\n", (A == 1) ? "true" : "false");
             printf("B is saying %s.word\n", (B == 1) ? "true" : "false");
             printf("C is saying %s.word\n", (C == 1) ? "true" : "false");
         }
    return 0;
}

执行一次后就直接goto了。。。。你应该把if放上面去，再把goto放if里面去，然后试试。。。


[ 本帖最后由 huangapple 于 2011-1-13 10:45 编辑 ]

c是清白的。

#include <stdio.h>

int main()
{
    int A;
    int B;
    int C;
    int count = 0;
   
    for (A=0; A<2; A++)
    {
        for (B=0; B<2; B++)
        {
            for (C=0; C<2; C++)
            {
                count += ((A == 1 && B == 0) || (A == 0 && B ==1));
                count += ((B == 1 && C == 0) || (B == 0 && C == 1));
                count += ((C == 1 && A == 0 && B == 0) || (C == 0 && A == 1 && B== 1));
                if (count == 2)
                    goto finish;
               
            }
        }
    }
   
   finish :

             printf("A is saying %s.word\n", (A == 1) ? "true" : "false");
             printf("B is saying %s.word\n", (B == 1) ? "true" : "false");
             printf("C is saying %s.word\n", (C == 1) ? "true" : "false");

    return 0;
}

#include <stdio.h>

int main()
{
    int A;
    int B;
    int C;
    int count = 0;
   
    for (A=0; A<2; A++)
    {
        for (B=0; B<2; B++)
        {
            for (C=0; C<2; C++)
            {
                count += ((A == 1 && B == 0) || (A == 0 && B ==1));
                count += ((B == 1 && C == 0) || (B == 0 && C == 1));
                count += ((C == 1 && A == 0 && B == 0) || (C == 0 && A == 1 && B== 1));
                if (count==3)  goto finish;//怎么的算法我不知道，但是根据你的意思，你看这样可以不？  
             }         
        }
    }
   
    finish:
             printf("A is saying %s word\n", (A == 1) ? "true" : "false");
             printf("B is saying %s word\n", (B == 1) ? "true" : "false");
             printf("C is saying %s word\n", (C == 1) ? "true" : "false");
             return 0;
}

逻辑运算，和逻辑   应该差好多。

学习.

口算了下B真话