我初始了一个9×9宫格（x,y是lable坐标），行符合数独规则（1~9不重复），但是怎么检验列呢？我的想法是遍历之前有的数字。如果不一样就继续检验，如果一样就重新随机个数字再从头开始重新检验。但是不知道怎么写，或者有没有更好的方法呢？谢谢！

public Form1()
        {
            InitializeComponent();

            Label[,] sudoku = new Label[9, 9];
            Random rd = new Random();
            string[] index = new string[9];
            int y = 25;
            for (int i = 0; i < 9; i++)
            {
                for (int k = 0; k < 9; k++)
                {
                    index[k] = (k + 1).ToString();
                }

                int size = 9;
                int x = 98;
                for (int j = 0; j < 9; j++)
                {
                    int number = rd.Next(0, size - 1);

                    sudoku[i, j] = new System.Windows.Forms.Label();
                    sudoku[i, j].Location = new System.Drawing.Point(x, y);
                    sudoku[i, j].BackColor = System.Drawing.Color.DarkGray;
                    sudoku[i, j].Size = new System.Drawing.Size(30, 30);
                    sudoku[i, j].BorderStyle = System.Windows.Forms.BorderStyle.Fixed3D;
                    sudoku[i, j].Font = new System.Drawing.Font("Verdana", 9F, System.Drawing.FontStyle.Bold, System.Drawing.GraphicsUnit.Point, ((byte)(0)));
                    sudoku[i, j].TextAlign = System.Drawing.ContentAlignment.MiddleCenter;

                    sudoku[i, j].Text = index[number];
                    Controls.Add(sudoku[i, j]);

                    index[number] = index[size - 1];
                    size--;
                    x = x + 30;
                }
                y = y + 30;
            }

        }

搜一下，看看别人的作品是怎么做的吧！！

[ 本帖最后由 c1_wangyf 于 2010-12-31 08:41 编辑 ]

比如我在检验第一列的时候，当前的数字与之前的数字相等，怎么让重新随机出来的数字再回到循环里面从t=0开始重新检验呢？

int number2 = rd.Next(1, 10);
            string[] s = new string[9];
            s[0] = sudoku[0, 0].Text;
            int indexA = 1;
            for (j = 0, i = 1; i < 9; i++)
            {
                for (int t = 0; t < indexA; t++)
                {
                    bool flag = true;
                    if (sudoku[i, j].Text != s[t])
                    {
                        flag = false;
                        continue;
                    }
                    if (flag)
                    {
                        sudoku[i, j].Text = number2.ToString();
                    }
                }
                s[indexA] = sudoku[i, j].Text;
                indexA++;
            }