用户输入行数.输出菱形.(菱形的宽和高相等且为奇数,至少5行.)
n=5
  x
 x x
x   x
 x x
  x

为啥我编的一运行就是满天星呢?

#include <stdio.h>
void main ()
{
    int i,j,n;
    printf ("输入菱形的宽度n:\n");
    scanf ("%d",&n);
    while (n<5||n%2==0)
    {
        printf ("输入错误,请重输:");
        scanf ("%d",&n);
    }
    for (i=1;i<=n/2+1;i++)
    {
        if (i=1)
        {
            for (j=1;j<=(n/2+1-i);j++)
                printf (" ");
            printf ("*");
        }
        else
        {
            for (j=1;j<=(n/2+1-i);j++)
                printf (" ");
            printf ("*");
            for (j=1;j<=(i*2-3);j++)
                printf (" ");
            printf ("*\n");
        }
    }
    for (i=n/2;i>0;i--)
    {
        if (i=1)
        {
            for (j=1;j<=(n/2+1-i);j++)
                printf (" ");
            printf ("*\n");
        }
        else
        {
            for (j=1;j<=(n/2+1-i);j++)
                printf (" ");
            printf ("*");
            for (j=1;j<=(i*2-3);j++)
                printf (" ");
            printf ("*\n");
        }
    }
}

 

[ 本帖最后由 d6230619 于 2010-11-19 20:29 编辑 ]

没仔细看 感觉比我这个还乱

#include"stdio.h"
int main()

{
    int i,j,k,m;
    int l=0;
    printf("input the number:\n");
    while(1)
    {
        scanf("%d",&k);
        if(k % 2 == 0)
            printf("wrong,again\n");
        else
            break;
    }
    i=k/2+1;
    for(j = 1; j <= i; j++)
    {   
        for(m = 1;m <= k; m++)
         {
             if(m == (i+l)||m == (i-l))
                 printf("*");
             else
                 printf(" ");
         }
         printf("\n");
         l++;
    }
    for(j = i+1; j <= k; j++)
    {   
        for(m = 1;m <= k; m++)
         {
             if(m == (i+l-2)||m == (i-l+2))
                 printf("*");
             else
                 printf(" ");
         }
         printf("\n");
         l--;
    }
    return 0;
}

这个应该行

哈哈   我看看先...  不过脑袋比较乱..迷糊的要死..

谢了!  启发很大...   

不过我还是没搞明白我那个错哪了..