Write a C program that prints out all different possibilities of obtaining ￡1(1 pound)
using coins of values 2 pence, 5 pence, and 10 pence. Indicate how many
possibilities have been found. The output of your program may look like:

￡1 = 50 x 2p
￡1 = 45 x 2p + 2 x 5p
￡1 = 40 x 2p + 4 x 5p


…
In total, there are 66 possibilities to make ￡1.


Hint: You may use loops to generate the number of coins n2, n5, and n10 of value 2,
5, and 10 pence respectively and use the formula ￡1=100p=2*n2+5*n5+10*n10.

#include "stdio.h"
void main()
{
    int x,y,z;
    for(x=0;x<100;x++)
      {
          for(y=0;y<100;y++)
            {
                for(z=0;z<100;z++)
                  {
                      if(x*2+y*5+z*10==100)
                      printf("$1=%d*2p+%d*5p+%d*10p\n",x,y,z);
                  }
            }
      }  
   
}