using System;
using System.Collections.Generic;

public class Example
{
    public static void Main()
    {
        List<string[]> a = new List<string[]>();
        string [] b=new string [2];
        
        b[0] = "adf";
        b[1] = "rtgh";
        a.Add(b);
        b[0] = "456ret";
        b[1] = "nt567";
        a.Add(b);
        b[0] = "dfh55t";
        b[1] = "nderthert";
        a.Add(b);

        Console.WriteLine(a.Count .ToString ());
        foreach (string[] s in a)
        {
            Console.WriteLine(a[0][0]);
            Console.WriteLine(a[0][1]);
        }
        


    }
}


得到的结果是三组相同的字符数组
怎样才能前两项不被覆盖啊

那你试下用3次string [] b=new string [2];
string [] c=new string [2];
string [] d=new string [2];

List中存储的是对象的地址

[[it] 本帖最后由 Y08M09D26 于 2008-11-17 15:15 编辑 [/it]]

正解
 string [] b=new string [2];
        
        b[0] = "adf";
        b[1] = "rtgh";
        a.Add(b);
 string [] b=new string [2];
        b[0] = "456ret";
        b[1] = "nt567";
        a.Add(b);
 string [] b=new string [2];
        b[0] = "dfh55t";
        b[1] = "nderthert";
        a.Add(b);

我明白了，谢谢指点

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