求解一个小程序
N〈 10001+(1+2)+(1+2+3)+(1+2+3+4)+(1+2+3+4+5).....+(1+2+3.....+n)
刚学
不会
哪位高手路过就指点下
2007-09-18 13:14
2007-09-19 09:32
int sum=0;
for(int i=1;i<=n;i++)
{
for(int j=1;j<=i;j++)
sum+=j;
}
2007-09-19 15:40
2007-09-19 19:09
2007-09-22 10:17
2007-09-22 13:56
2007-09-23 00:31
#include<iostream.h>
void main()
{
long double n=1,sum=0,sum1=0;
while(n<1000)
{
for(int i=1;i<=n;i++)
{
sum+=i;
}
sum1+=sum;
n++;
}
cout<<sum1<<endl;
getchar();
}
while和for循环还是不上吧！呵呵！
2007-09-23 00:33
2007-09-24 22:16
2007-09-24 22:44
